The boat has an overall length of
36 ft and the lateral wind draft measures 190 sq.ft. It is required
that the bow can still be controlled easily when a wind force of 20
knots applies. At a wind force of 20 knots, the wind pressure is:
p = 1.0 to 1.9 lbf/sq.ft i.e.p. (average) 1.45 lbf/sq.ft.
The required torque reads:
T = windpressure x wind draft x reduction factor x distance center
of effort to pivot point, (=appr. half the ship's length)
T = 1.45 lbf/sq.ft x 190 sq/ft x 0,75 x 36 ft/2 = 3719 ft.lbs.
The required Thrust Force is calculated as follows:
F = Torque/distance between the center of bow thruster and the
pivot of the boat
= 3719 ft/lb / 34.5 ft = 107.8 lb
The VETUS bow thruster which is most suitable for this
particular vessel is the 121 lbf model.
Always bear in mind that the effective performance of a bow
thruster will vary with each particular boat, as the displacement, the
shape of the underwater section and the positioning of the bow
thruster will always be variable factor. |